# My solution

would be

``` __uint64_t test = 0; for (int i=0; i<64; i++) { if (i%2==0) // if even, shift left test = test << 1; else { // if uneven, shift left and make the first digit 1 (OR 1) test = test << 1; test |= 1; } } printf("Resutltat %lld", test); ```

Always open for recommendations and more elegant solutions

Mine is similar, just the if-check is vice versa:

[code] unsigned long long myNumber = 0;

``````for (int i = 0; i < 64; i++) {
if (i % 2) {
myNumber = myNumber << 1; // myNumber <<= 1; would be possible as well
myNumber = myNumber | 1; // myNumber |= 1; would be possible as well
}
else
{

myNumber = myNumber << 1; // myNumber <<= 1; would be possible as well
}
}

printf("myNumber: %lld\n", myNumber);[/code]``````

this is what I had done

``````
uint64_t big =0;

int iI = 0;
int insidecount =0;

for ( iI = 0; iI < 63; iI ++){
big = big << 1;

if (insidecount % 2 ==0){
big = big + 0x01;

}
insidecount++;

}

printf("Variable in Hex is  %llx\n", big);
printf("Variable in Decimal is %llu\n",big);

``````