// Silver Challenge
var Nevada = [“Clark County”: [1, 2, 3], “Bear County”: [4, 5, 6], “Shark County”: [7, 8, 9]]
for (county, zips) in Nevada {
print("(county) has the following zip codes: (zips)")
For the gold challenge, I tried to eliminate any hardcoded values in the code so it would automatically work with any number of counties. I also didn’t want to have any extra loop counters, just have it automatically detect the various ending points.
var stateZipcodes = ["Calhoun": ["12345", "23456", "34567", "45678", "56789"],
"Fayette": ["12346", "23457", "34568", "45679", "56780"],
"Houghton": ["54321", "65432", "76543", "87654", "98765"]]
var output = "Georgia has the following zip codes: ["
let spaces = String(repeating: " ", count: output.characters.count)
print(output, terminator:"")
let countyArray = Array(stateZipcodes.keys)
for county in countyArray
{
let countyZipcodes = stateZipcodes[county] ?? []
for zipcode in countyZipcodes
{
print(zipcode, terminator:"")
if (zipcode != countyZipcodes.last)
{
print(", ", terminator:"") // still more zip codes on this line
}
else if county != countyArray.last
{
print(",") // last zip code on this line but not the last line, so use normal line termination
print(spaces, terminator:"") // and indent the next line
}
else
{
print("]") // last zip code in last county, so we're done
}
}
}
The only potential issue with this code is that if a county has more or less than 5 zip codes, you won’t get 5 zip codes printed on each line. To fix that you’d have to count the number of zip codes printed and start a new line after every fifth one, not just after each county.
The first solution in this thread is way more elegant than mine. But, this is what I came up with for the Silver Challenge.
//Silver Challenge
//Create arrays of zips
var polkZip = [30306, 30307, 30308, 30309, 30310]
var booneZip = [30311, 30312, 30313, 30314, 30315]
var marshallZip = [30301, 30302, 30303, 30304, 30305]
//Create a dictionary of counties that maps to the zip arrays
var counties = ["Polk": polkZip, "Boone": booneZip, "Marshall": marshallZip]
//Create an array to hold all zips in the dictionary
var zipHolder = [0]
//This is the weird bit. I have to initialize the array with something and then remove it from the array. If I try to append to the array when it is empty I get errors.
zipHolder.remove(at: 0)
// loop through them to pull out the values for each county
for zips in counties.values {
// Get a count of the number of zips in the given array
var countyZipCount = zips.count
//Set a counter so that we can iterate through each array and put the values in each array into the zipHolder array
var counter = 0
while counter < countyZipCount {
zipHolder.append(zips[counter])
counter += 1
}
}
// Print out the long list of Zips
print("Iowa has the following zip codes: \(zipHolder)")
I would appreciate any advice on initializing the array before using it. It seems I MUST put a value in the array before appending new values to it. However, if I give the array an initial value and then remove it, all is fine. Hmmmmmm
Read page 82: If you just declare an Array and then try to append you get an error.
The solution is to create an empty array: var zipHolder = [Int] (). Then U don’t need to remove anything. With empty array you do 2 things declare and initialize.
1 Like
//Silver Challenge
Update Here’s my new solution working as expected. In as few lines as possible.
import Cocoa
var georgia = [“Cobb” : [30064, 30193, 38263, 30060, 34920] , “Fulton” : [37283, 30312, 38943, 30314, 36647 ] , “Gwinnett” : [30028, 36462, 32938, 32389, 31119] ]
var resultArray : [Int] = []
for zipCodes in georgia.values
{
for zip in zipCodes
{
resultArray.append(zip)
}
}
print(“Georgia has the following zip codes :” , resultArray)
//Georgia has the following zip codes : [37283, 30312, 38943, 30314, … ]
Similar solution here:
var ctZips = ["Fairfield": [06464,06614,06615, 06515, 06516],
"New Haven": [10001, 10111, 10101, 10005, 11003],
"Litchfield": [07711, 07001, 05523, 08899, 02020]]
var bigZipList = Array<Int>()
for zip in ctZips.values {
bigZipList += zip
}
print("CT has the following zip codes: \(bigZipList)")
1 Like
Maybe mine is weird…
import Cocoa
var china = [“hubei”:[101,102,103,104,105],
“shanghai”:[201,201,203,204,205],
“zhejinag”:[301,302,303,304,305],
“hunan”:[401,402,403,404,405]];
let post = Dictionary<String,Double>();
for post in china{
print(post);
}
If you post your code between a pair of 3 back tick marks (```), you will make it easier to read:
var postCodes = [
"hubei" : [101,102,103,104,105],
"shanghai": [201,201,203,204,205],
"zhejinag": [301,302,303,304,305],
"hunan" : [401,402,403,404,405]];
// pretty print...
var maxKeyLen = 0
for (key, _) in postCodes {
if maxKeyLen < key.count {
maxKeyLen = key.count
}
}
for (key, value) in postCodes {
let padding = String (repeating: " ", count: maxKeyLen - key.count)
print ("\(key) \(padding): \(value)");
}
should output:
hunan : [401, 402, 403, 404, 405]
shanghai : [201, 201, 203, 204, 205]
zhejinag : [301, 302, 303, 304, 305]
hubei : [101, 102, 103, 104, 105]
thank you ，I think I have mastered these contents，Thank you very much your reply.
Maybe we can make a friend， My name is 张威,My hometown is in China。
I’m sorry to reply you so late。
we can now send messages by email at any time
Here goes my code:
//Silver Chapter.10
let zipCodesA = [94541, 94542, 94543, 94544, 94545]
let zipCodesB = [94551, 94552, 94553, 94554, 94555]
let zipCodesC = [94561, 94562, 94563, 94564, 94565]
let california = ["Alameda": zipCodesA, "Contra Costa": zipCodesB, "San Francisco": zipCodesC]
var zipContainer = [Int]()
for i in zipCodesA {
zipContainer.append(i)
}
for i in zipCodesB {
zipContainer.append(i)
}
for i in zipCodesC {
zipContainer.append(i)
}
print("California has the following zip codes: \(zipContainer)")
//Silver: mo'betta, refactored for/in loop
for i in california.values {
for zip in i {
zipContainer.append(zip)
}
}
print("California has the following zip codes: \(zipContainer)"
1 Like
Most understandable code solution to the gold challenge that I’ve found yet. Nice work.
// Silver Challenge that is what i have (
var california = [“San Bruno”:(94066, 94065, 94067, 94061, 94063),
“Pacifica”: (94044, 94042, 94041, 94045, 94048),
“Sunnyvale”: (94085, 94088, 94087, 94089, 94090)]
for city in california {
print("(city.key) zip code is: (city.value) \n")
}
Silver Solution
var countyCodes: [String: [Int]] = [:]
countyCodes = ["Cimeria": [30306,30307,30308,30309,30310],"Atlantis": [30311,30312,30313,30314,30315], "Stygia": [30301,30302,30303,30304,30305]]
var allCodes: [Int] = []
for (_ , values) in countyCodes
{
allCodes += values
}
print("Hyborian empire has following counties: \(allCodes)")I am new to coding so …
I’m using the 3rd Edition Swift Programming by Mikey Ward
The Silver Challenge is to create a dictionary with three teams and five players per team. Then print all fifteen players.
My solution:
let teams = [
"Team1": ["T1P1", "T1P2", "T1P3", "T1P4", "T1P5"],
"Team2": ["T2P1", "T2P2", "T2P3", "T2P4", "T2P5"],
"Team3": ["T3P1", "T3P2", "T3P3", "T3P4", "T3P5"]
]
let players = Array(teams.values.joined())
print("The Conference has the following players: \(players).")
Console shows:
The Conference has the following players: [“T1P1”, “T1P2”, “T1P3”, “T1P4”, “T1P5”, “T2P1”, “T2P2”, “T2P3”, “T2P4”, “T2P5”, “T3P1”, “T3P2”, “T3P3”, “T3P4”, “T3P5”].
The Gold Challenge is to print the team name on one line then its players (one at a time) on each line below the team name.
My solution:
print()
for (team, player) in teams {
print("\(team) has the following players:")
for pl in player {
print("\(pl)")
}
print()
}
Console shows:
Team1 has the following players:
T1P1
T1P2
T1P3
T1P4
T1P5
Team2 has the following players:
T2P1
T2P2
T2P3
T2P4
T2P5
Team3 has the following players:
T3P1
T3P2
T3P3
T3P4
T3P5
Can someone let me know if I did this right?