My solution to challenge at the end of chapter 3


#1

Here is my code to the answer for the challenge:

#include <stdio.h>

int main(int argc, const char * argv[]) {
    float firstFloat = 3.14;
    float secondFloat = 42.0;
    
    double theSum = (double)firstFloat + (double)secondFloat;
    
    printf("The sum of %f and %f is %f.\n", firstFloat, secondFloat, theSum);
    
    return 0;
}

I know that typecasting hasn’t been covered yet, but from some other courses I took I learned that lesson.

Here is my output:

The sum of 3.140000 and 42.000000 is 45.140000.

What typecasting does is change the float to a double so that the precision is kept.